00:02 Hello, my name is Dorcas Awaye.
00:14 I'll be taking you mathematics today,
00:16 and today's topic is algebraic processes,
00:18 talking about simple equations.
00:20 At the end of today's teaching,
00:24 you should be able to translate word sentences
00:26 into mathematical equations,
00:28 use mathematical equations to represent word sentences,
00:32 solve simple equations and cross-check your answers.
00:36 Translate in word sentences into mathematical equations.
00:41 All algebraic expressions can be very useful
00:43 when you need to solve everyday problems.
00:46 It allows you to use variables
00:47 as representations of numbers where the value may vary.
00:51 For example, you get 500 NARA Pokemon every month,
00:56 and you know that for that month,
00:59 what you do with it is you spend it on sweets,
01:03 transports, and data for your mobile.
01:06 So you can represent these variables
01:08 with alphabet to make an algebraic expression
01:12 or an algebraic equation.
01:14 500 NARA Pokemon every month
01:17 is what you get in total every month.
01:20 So we began to express our words into numbers,
01:26 expressing word problems into algebraic expressions,
01:30 into equations.
01:31 This is how you go about it.
01:33 You go by the word one after the other
01:35 and then you take it easy to interpret them.
01:38 Suppose you get 500 NARA Pokemon every month
01:42 and you want to keep track of the money you spend.
01:44 You know, because you spend money on sweets,
01:47 transports, and data for your mobile,
01:48 it may not be constant every month.
01:51 You may spend more on sweets in January
01:55 than in February.
01:57 You may spend more on transports and data
02:00 than you spend on sweets in another month.
02:03 This is why algebraic expressions, equations,
02:05 or algebra in mathematics are important.
02:08 So you can easily keep track of how you spend.
02:11 So we can create any question from this.
02:14 So you have the money available as 500 NARA
02:17 and you have what sweets,
02:23 sweets you have data and then you spend it on transport.
02:28 So you can easily represent this with Z,
02:34 represent this with D and represent this with S.
02:39 So for your 500 NARA, this is,
02:43 to know how much is left every month,
02:45 say how much money is left or money available at time Z.
02:53 It's equal to the amount you get every month,
02:57 minus the combination of sweets,
03:01 plus data, plus transport.
03:06 So this using our algebraic expressions
03:09 can easily be put simple.
03:12 The entire word here can just be put simple,
03:14 simply like this, with algebraic expressions.
03:19 Use footsteps in solving world problems
03:22 with our algebraic expressions.
03:24 For example, you have three consecutive numbers
03:27 can be represented as X, X plus one, and X plus two.
03:30 That is, the first number is X, second is X plus one
03:34 and the third is X plus two.
03:36 If you have four consecutive numbers,
03:38 then you have X, X plus one, X plus two, X plus three.
03:42 So those are four times.
03:45 When you hear more than, for example,
03:48 maybe five more than, maybe I earn five units more than my brother.
03:58 That is X plus five.
04:00 Because I haven't mentioned how much I earn.
04:02 So how much I earn can be represented with X.
04:05 So if how much my brother earns is X, or X in the era,
04:09 and I say I earn five NARA more than my brother,
04:12 that means I earn X plus five,
04:15 which is also an algebraic expression.
04:18 Because I have not even told you
04:20 how much my brother earn entirely.
04:21 Express is in terms of algebraic expression, which is just X.
04:25 Less than, for example, less than X, that is X minus five.
04:30 Double or twice, for example, has these two times,
04:34 whatever it is, two times X, or two times Y.
04:37 That is two Y or two X, as the case may be.
04:41 How, for example, can have Y divided by two?
04:45 Total costs, for example, maybe cost of pens and rulers.
04:49 The total cost would be expressed in P plus R.
04:54 Every other triangle, length times this breath,
04:57 as L times B parameter of a rectangle,
05:00 2L plus 2B.
05:01 That is how we express words in algebraic terms.
05:06 Let me go with this, let's start with this example.
05:11 A father is X years old.
05:14 His daughter is currently half his age.
05:17 Our horde will be his daughter B in 10 years time.
05:20 If a father is 10 years old, say father is X years old.
05:30 This is his age.
05:32 Just as your age is maybe two years old.
05:35 Or 3, 5, 12, like that.
05:40 So we don't know the exact value we represented
05:42 it with X years old.
05:44 Our horde will be his daughter.
05:46 Then his daughter is currently at the moment, half is age.
05:50 Remember, his daughter, which is half his age,
05:56 I told you when you were talking about half,
05:57 that is divided by two.
05:58 So his daughter's age, daughter's age now,
06:02 is X divided by two.
06:06 He can also write it as X divided by two, like this.
06:13 Our horde will be his daughter B in 10 years time.
06:17 So in 10 years time, that is when you have plus 10 years,
06:23 that is what it means.
06:24 In 10 years time, our horde will be the daughter B.
06:27 So daughter's age would be is equal to X divided by two plus 10.
06:41 In 10 years time, daughter's age will be this expression.
06:51 So these are your express world problems in algebraic expressions.
06:57 If there was a value given for X, then we
07:04 could find out what the exact age is.
07:07 But as it is now, there's no value.
07:08 We leave it the way it is.
07:10 Second example, a shop owner sells maize at Sunera Parkop.
07:15 She also sells rice Parkop at double the price of the maize.
07:21 If she sold 50 cups of maize and 45 cups of rice,
07:25 what was her income?
07:27 A shop owner sells maize at Sunera Parkop.
07:31 So for one cup of maize, one cup of maize,
07:41 we have Sunera.
07:56 One cup of maize is Sunera.
07:58 She also sells rice Parkop at double the price of the maize.
08:03 So one cup of rice is double the price of maize.
08:08 One cup of rice of one cup is double the price.
08:20 That is two times the price of maize.
08:23 So that is two times the price of maize, which is two times two.
08:28 Because this is Sunera.
08:30 Double the price of maize is the price of rice.
08:34 So if I had not put two here, for example,
08:38 if I had said a cup of maize is say X-Nera or Y-Nera,
08:41 I would have written Y-Nera here.
08:44 And then if she sells a cup of rice as double the price of maize,
08:50 that would be two Y, which is the same thing as two times Y.
08:55 So two times two.
08:58 So she sells a cup of rice at four Nera.
09:04 If she sold 50 cups of maize and 45 cups of rice, what was her income?
09:09 So 50 cups of maize, 50 cups of maize at Sunera of maize is two times 50.
09:23 Because one cup is Sunera.
09:25 So 50 cups of maize would be two times 50, which gives you on red.
09:31 And then she sold 45 cups of rice, 45 cups of rice.
09:43 So 45 times two, 45 now would be 45 times four.
09:48 Because a cup of rice is four Nera, so four multiplied by 45.
09:54 So our income is two times 50 plus four times 45, which is on red.
10:15 Four times 45 would give you 180.
10:21 So our total income is 280 Nera.
10:30 So if these values that we imputed, that is 50 cups.
10:34 And we know the number of cups you bought and then 45 cups.
10:40 Rather, if two Nera was not inclusive in this expression,
10:45 if we did not give information that a shop owner sells maize as--
10:50 let me say a shop owner sells maize as a Q Nera.
10:55 Say maize is equal to Q Nera.
11:02 Or we don't know.
11:04 Say a shop owner sells maize as the rate of Q.
11:09 So we say Q. And rice adds double the price of maize.
11:21 That is two times Q. If she sold 50 cups of maize and 45 cups of rice,
11:29 what was her income?
11:30 So 50 cups of Q, that is 50 of Q, 50 Q plus--
11:44 this is 2Q plus 2Q times 45.
11:52 So we have 50 Q plus 90 Q. Two times 45 is 90.
12:06 So we have 90 Q. So because we have the same terms,
12:10 we can easily add them together, which gives you 140 Q.
12:18 So because the value of Q can vary, just because we had 2 Nera already,
12:25 that was how we could get the value 280.
12:28 So Q, if the price changes to 3 Nera, 4 Nera,
12:31 we can easily use this expression to get how much our income is as price varies.
12:40 So these other examples, I believe, you can solve them.
12:44 I could solve one of them, or let me solve this.
12:56 The sum of three consecutive numbers is 11.
12:59 Remember when we talk about consecutive numbers,
13:02 that is, say, this is example 4.
13:10 I want to start with 4.
13:11 First, let's do 4.
13:13 Now, sum of three consecutive numbers is 11.
13:15 So three consecutive numbers.
13:17 The first one is A. The second one is A plus 1.
13:21 It can be Y. It can be C O. And the third one is A plus 2.
13:25 When you hear consecutive numbers, just put it like this.
13:28 So if the sum of all of these gives 11, this is how you express it.
13:32 The sum of these three gives 11.
13:34 So A plus 1 plus A plus 2 all gives you 11.
13:44 And the first of the three numbers is A, as it is C in A, determine the rest.
13:52 These are the rest, but what is the value?
13:54 That is what we want to get now.
13:56 Because we can get the value.
13:58 See, let's see if we can get the value.
14:00 So we have A plus A plus 1 plus A plus 2 equals 11.
14:08 Remember, like I taught you earlier, you're going to bring like times together.
14:11 So A plus A plus A plus 1 plus 2 equals 11.
14:19 So A in three places is 3A plus 3 equals 11.
14:27 So how do you solve it?
14:29 Using the inverse operation.
14:30 And you may not use inverse operation.
14:32 Let me teach you this.
14:33 You can't go like this.
14:34 Once you have something like this, you want to always find a way to make the one with
14:38 a variable alone on one of the sides, making it the subject of the formula.
14:45 So you can say 3A plus 3, the inverse of 3 is minus 3, and then you have 11 minus 3.
14:58 So you have 3A plus 0 equals 8.
15:05 So 3A equals 8.
15:09 We are not looking for 3A.
15:10 We are looking for A.
15:12 So A would be 8 divided by 3.
15:18 So A equals 8 over 3.
15:23 So A is 8 over 3.
15:25 The question is to determine the rest.
15:27 So if A is 8 divided by 3, the rest is A plus 1.
15:32 The first is A plus 1, which is 8 over 3 plus 1.
15:38 The second is A plus 2, which is 8 over 3 plus 2.
15:47 So moving on to this example.
15:51 It's small such as of milk cost X-Nyron, milk, X-Nyron, and it's small such as of noodles
16:13 cost 20 more.
16:15 So noodles is X plus 20.
16:25 What are the cost of 4 such as of milk and 8 such as of noodles?
16:32 So for 4 such as of milk, 4 such as of milk, that's 4, say 4 milk, 4 milk such as X and 4
16:51 places, X in 4 places, which is the same as 4 X.
17:01 You can just say 4 X, so you can say X plus X plus X plus X.
17:05 This is a cost of 4 such as of milk.
17:07 And 8 such as of noodles, 8 noodles would be since noodles is X plus 20.
17:18 So you have 8 times of X plus 20.
17:27 So 4 such as of milk is 4 X, 8 such as of noodles is the same thing as, now we can now,
17:37 we want to expand this.
17:38 Just the way I taught you to expand in the previous lesson 8 into bracket X plus 20.
17:48 Using the distributive law, you use this to multiply this and then use the same to multiply
17:53 this as well.
17:54 So you have 8 times X plus 8 times 20.
18:04 So you have 8 X plus 160.
18:10 So this is the cost of 8 such as of noodles of noodles.
18:20 We've come to the end of the examples.
18:25 You have your exercise, a pencil costs X, Nara, a ruler costs 10, Nara less than a pencil.
18:32 Remember the tips, you can just go back to the tips to know what to use for each of them.
18:37 A pencil costs 5 Nara more than a ruler.
18:39 The price of a small exercise book is twice the price of a ruler, calculate the cost
18:43 of 3 pencils, 2 rulers and 4 exercise books.
18:46 So you have like 3 variables in this word problem.
18:51 From the tips I gave you, you should be able to decipher which of the expressions to use.
19:00 The second is the sum of 4 consecutive numbers which is 16.
19:04 Find the numbers.
19:05 We did an example that has to do with 3 consecutive numbers.
19:08 So I believe you should be able to solve this.
19:11 The length of a rectangle is 3 cm more than its breadth, calculate the perimeter of the
19:17 rectangle.
19:18 From the tips, I believe you should be able to solve this and it should be easy.
19:25 We've come to the end of today's class.
19:27 Thank you so much for watching.
19:29 My name is Dorkas Aoye, till next time.