Graphical Method of Simultaneous Linear Equations
This lesson teaches how to solve simultaneous linear equations using the graphical method. Students will learn to create a table of values, plot the equations on a graph, and identify the point of intersection as the solution. The focus is on using the x and y axes correctly.
- 00:00 “Hello, my name is Oyase Ose Sunday. I'm taking a maths JSS-3 class, but we have an interest in topic for today. The topic says simultaneous linear equations, we'll be looking at the graphical method of simultaneous linea...”
- 03:13 “a plane, if you are expected to solve using graphical method. There's a need to work with the graph. Now, solve graphically the system of some of those three line equations. x plus y equal to 5. x minus y equal to 3. Now...”
- 20:36 “like, connecting each. You could see from the graph, the 2 straight line intersect at what? 4 and 1. So, therefore, x equal to 4 y equal to 1 is the solution for the given system of what? Simultaneous what? Equation. Wit...”
Solving Linear and Quadratic Equations
This lesson covers the methods for solving simultaneous linear and quadratic equations using substitution. It explains the definitions of linear and quadratic equations and demonstrates how to manipulate these equations to find solutions.
- 00:02 “Hi, everyone. My name is Baruwa R.O. Mrs. I'm your master teacher for today. And the topic we'll be looking at is some autonomous equation, one linear and one quadratic. At the end of this section, you should be able to...”
- 24:56 “You solve accordingly. Then you will get the value of x and y. So when y is equals to two, from equation three, x is equals to five minus y. Substitute the value of y, your f is equals to five minus two. And the x, we gi...”
- 07:31 “So substitute its back. Substitute X is equals to minus two into equation three, which is Y is equals to four minus two X. Your X is minus two. There you have Y is equals to four minus two, multiplied by minus two. And Y...”
Exponential Equations
This lesson covers the definition and properties of exponential equations. It explains how to solve exponential equations of linear form by ensuring the bases are the same. Examples are provided to illustrate the process of finding the unknown variable in these equations.
- 08:56 “of linear of quadratic form. And that of x or x is number two is for exponential equation of a linear form. So therefore we can use this the method that we use in our previous examples to solve this as a size. So thanks...”
- 06:18 “two raised to power x or raised to power two. We use what we call the power law yeah. So minus six raised to power two raised to power x plus eight equals zero. So let's why equals two raised to power x. So it means wher...”
Similar Shapes
This lesson covers the identification of similar shapes such as triangles, rectangles, squares, cubes, and cuboids. It explains the criteria for similarity, including proportional sides and equal angles. The lesson also includes methods for enlarging figures using scale factors and calculating lengt
- 25:22 “these 2, if it cannot be in this form then your answer is wrong, now the last part is applying it to water problem, how do we apply it to water problem, how using your scalar factor to solve a problem, olatical wants to...”
- 28:50 “We said that solution. A scalar factor is that of the longest. The longest, the first side given, the first side given is the wall. The longest, remember, over longest of the beak, those sides that are given, and the lon...”
- 29:44 “That will give you a divided by that will 3. So your K factor, your scalar factor is 3. That means the shadow of the lamp, compared to the shadow of Ola de Poe is 3 times. Take note of that. Now calculate the height of t...”
Roots of Quadratic Equations
This lesson covers how to find the sum and product of the roots of a quadratic equation. It also explains how to form a quadratic equation given the roots and states the conditions for equal roots, real roots, and no roots. Additionally, it discusses the relationship between a line and a curve in te
- 11:22 “that means I'm gonna have X minus five into X plus four equals zero. So when I have that, what comes out is this. In the same vein, I can expand. You can just write for your teacher to know, expand. So your teacher will...”
- 15:18 “you can just make it three X over two, and you now go for minus two of five times X, that gives you minus two X over five. And the last one minus two of five times three over two, that gives you minus, okay, six over 10....”
- 14:33 “and put it together, that is, you have X minus two over five, two over five, okay, into X plus three over two. All right. Well, with this, you can as well expand and come out neatly, that gives you X squared for X times...”
Basic Operations on Whole Numbers
This lesson covers addition and subtraction of whole numbers, including how to align numbers by their place values. It also explains multiplication and division by 10, 100, and 1000, and introduces the use of the BODMAS rule for solving mixed operations.
- 40:39 “So, I've given you short method, now we go to the next question, which is using long division method, using long division method. So, now, so that's a question, that's question 2, using long division method, that's the f...”
- 41:36 “you'll put 6, 275 in the square root sign, then you have 5 written outside, I want to use the long division method now. So, now, 5 in 6 is 1, you write the answer here, 1, 5 in 6 is 1, so 1 times 5, 1 times 5 is 5, you w...”
- 00:56 “Number four, the learners should be able to multiply and divide by 10, 100, 1000, etc. Now, we go into the content of the topic. So we're going to start with addition and subtraction. When adding or subtracting numbers,...”
Cost of Production
This lesson covers the concept of cost in economics, focusing on the cost of production. It explains different types of costs, such as fixed and variable costs, and discusses the factors of production that contribute to overall costs.
- 16:53 “is equal to fixed cost, plus variable cost, take note of that, then how do I do the graph, very easy, draw your x and y, exist, remember this is your worth, your fixed cost, right, this is fixed cost, can you see, then y...”
- 12:08 “How do you calculate your fixed cost? For you to calculate your fixed cost, there is a formula for it, you say your fixed cost, which is also the same as well, which is also the same as total fixed cost, it's capital use...”
- 12:54 “So this is how you draw the graph, it's very simple, first cost is set to be worth, it's set to be horizontal to the x-axis, are we together, it's not more than that, okay? Then let's move to the next one, please, and th...”
Magnetic Fields
This lesson covers the concept of magnetic fields, including types of magnets such as bar magnets. It explains the flow of magnetic forces from the North pole to the South pole and the principles of attraction and repulsion between magnets. The lesson also touches on how to create a magnet and the c
- 36:13 “And sin 30 is what's sin 30 is equal to 0.5 or 1 over 2. Then, graph f is equal to 10 more than 7.2 times teris per minus 10 times 0.5. Now, let's make use of the calculator. We have 107.2 times 0.5.”
Introduction to Trigonometry
This lesson covers the basic concepts of trigonometry, including the measurement of angles and the definition of trigonometric functions. It explains the types of angles, the use of protractors for measuring angles, and the concept of quadrants in relation to angles. The lesson also introduces plane
- 03:56 “as what's called the radius. So we have this. This is the center. From here to here is radius. From here to here is radius. Radius, radius, radius, radius, up to infinity time. So there's a constant distance from the cen...”
- 10:58 “To-- let me call it y degree. So we call this 1. We call this 2. So how do we do this? Quickly, we say that 20 degrees to-- we recall that pi radian equal to 180 degrees. Pi radian equal to 180 degrees. So therefore, if...”
- 11:47 “So that means 20 degrees is equal to pi over 9 radians. And y degrees equal to pi over 8. What is y? If we want to solve this, we also apply the same concept to do that we have, again, pi radian equal to 180 degrees. And...”