Basic Operations on Whole Numbers
This lesson covers addition and subtraction of whole numbers, including how to align numbers by their place values. It also explains multiplication and division by 10, 100, and 1000, and introduces the use of the BODMAS rule for solving mixed operations.
- 33:38 “The number to be divided is called the division, and the number performing the division is called the divisor. So in this case, 20 is the dividend, and 5 is the divisor, so to divide it all number, that ends in zeros by...”
- 34:33 “So now walk a sample, all divisor. Now the first one using short division method, using short division method, calculate the following. Now the first one there, you have 1 a, 2, 1, 9, divided by 3, and b, you have h, o,...”
- 35:31 “And c, we have 1, 4, 5, divided by the chain. In the elementary school, in the elementary school you were taught, you were taught that, if you look at this two, 119 divided by 3, you want to divide it, you can use the kn...”
Whole Numbers and Prime Factorization
This lesson covers the expression of whole numbers and decimal numbers in standard form. It includes finding prime factors of numbers up to 200, determining the least common multiple (LCM), and finding the highest common factor (HCF). Additionally, it addresses perfect squares and square roots using
- 08:57 “get two, now using the division method, division method method B, also for clarification, let's see the division method now, in the division method, that's method B, it will give you, we have it as right out the division...”
- 11:19 “factor of 504 and 588 will follow the two methods, so we have example three, on the log, so I have followed the division methods, I have 504 and I have 588, now going to the process division method, now what's the divisi...”
- 09:44 “can two go in this, no, you start off with three, now, three into nine, that gives us what, three, it cannot go in 11, three can still go wrong, three, one, three into 11, cannot go, and the last one is 11, one, one, all...”
Polynomials and Their Properties
This lesson covers the definition of polynomials and their degrees. It explains how to divide a polynomial by another polynomial of lesser degree and introduces the remainder theorem. Additionally, it discusses how to find factors of polynomials and solve cubic equations using their roots.
- 05:38 “and this is what we are trying to divide. So, you can see that this is less than the power. The degree of polynomial is less than this one. This is 1 and this is 2. And p1 is being divided by p2. So, it's called dividend...”
- 04:49 “So, what if n, n is what we want to divide. And what we are using to divide is x plus 2. So, we want to use x plus 2 to divide 2 x plus b x. So, p1 must be less than the degree of p1, the degree of polynomial of p1 must...”
- 14:00 “7. We can easily, you know, in our example one that we discuss, you know, we have this. We can easily find the remainder using the long division method. And the remainder in that example number 1 gives us 0. So, it means...”
Whole Numbers and Their Properties
This lesson covers whole numbers, including their definition and characteristics. It explains how to express whole numbers and decimal numbers in standard form. The lesson also includes finding prime factors, least common multiples (LCM), and highest common factors (HCF) of numbers.
- 17:03 “it is division. We moved backward. That's out of a 7. So, if you look carefully, so we have, what do I have? I have 7, 7 over how many times do I have? I have 10 ways to power 6. Because of the sign of division, because...”
- 17:50 “and how do I do that? Now, this is 1 over, okay? 1 divided by this. I need to convert this into multiplication. How do I do that? That's the first question. How do I do that? That this one is bit, how do I do that? It be...”
- 18:36 “this is moving up, it becomes a minus. That's negativity. Take notes. It becomes very important. It becomes very important. Now, looking at it again, another example that we have in the part of division. So, you could ha...”
Addition and Subtraction of Fractions
This lesson covers how to add and subtract fractions with the same and different denominators. It explains finding the least common multiple (LCM) to create equivalent fractions for addition and subtraction. Examples are provided for practice.
- 00:00 “Hello everyone, I'm your Mathematics teacher, Esther Olochi-Ebebeke, and the topic of this lesson is addition and subtraction of fractions. By the end of this lesson you should be able to solve giving problems on additio...”
- 10:50 “then you get the answer for the remainder which is the oranges. So we have to go about that very simple. We have 1 over 3, plus 3 over 8, plus 1 over 6. So when you turn this to, the LCM of 3, 8 and 6 is 24. Remember whe...”
- 04:08 “and the denominator by a common number. So to have to have 24 at the denominator of five and six, I also multiply six by four to have 24. So it means also that I will multiply the numerator by four and the denominator by...”
Departmental Accounts
This lesson covers the definition and purpose of departmental accounts. It explains how to prepare these accounts to show the performance of different departments in a business. The lesson also discusses the advantages of using departmental accounts for comparison, error detection, and managerial as
- 26:48 “The rent is 4,200 NIRA. We want to share the rent of 4,200 NIRA among the three departments. So let's move this up. Okay, so for rent, remember we are sharing 4,200 NIRA among the three departments. And what is the ratio...”
- 22:51 “And what does that mean? It means that the departments A would take ratio 6. The department B would take ratio 6 and the department C would take ratio 6. So for salaries and wages, the departments A would take 6 divided...”
- 22:03 “we need to now apportion to the different departments on a particular basis. So we are told that now salaries, insurance and rents will be apportioned on the ratio 6, 6, 3. So now let's look at the value of our salaries...”
Converting Base 10 to Binary
This lesson teaches how to convert base 10 numerals into binary numbers using two methods: subtraction and successive division. Students will learn to identify the powers of 2 and apply them in the conversion process.
- 10:21 “We have done this using this subtraction method. I'm using the same number so that we can see for ourselves that, whichever method you use, you arrive at the same answer. That's the essence of me. Repeat the same numbers...”
- 09:34 “So, there's a 2 in 3. So, what do we do? The same thing here, 3 minus 2, given us 1. That means, well, I don't get 2. Because, we have 1 left here now. So, what do we have? We also have 1 left. So, just put it there. We...”
- 11:06 “It's the same thing we're going to do. The same line we use in doing SCM and SCM. That's the same line we're going to use in solving, trying to convert base 10 to base 2 using the successive division method. So, for the...”
Simplification of Algebraic Expressions
This lesson covers the definition of algebraic expressions and their components, including terms and coefficients. It explains how to identify like terms, perform arithmetic operations on similar terms, and simplify expressions by inserting or removing brackets.
- 25:31 “is the next one, or division. In the expression, you do multiplication next. So you use the distributive law to multiply the brackets by its coefficient. Remember that 4 times 3x means 4 times 3 times x. 16x plus 2 plus...”
Multiplication in Binary Numbers
This lesson covers the multiplication of 2-digit and 3-digit binary numbers. It explains the basic rules of binary multiplication and how to apply them in calculations. Students will learn to perform binary multiplication without borrowing.
- 15:40 “transferred to this place so that gives us plus one yeah plus one one plus one that's two we turn back here that gives us zero that what do I have then I have the last one transferred yeah that's plus one so plus one plu...”
Similar Shapes
This lesson covers the identification of similar shapes such as triangles, rectangles, squares, cubes, and cuboids. It explains the criteria for similarity, including proportional sides and equal angles. The lesson also includes methods for enlarging figures using scale factors and calculating lengt
- 11:57 “smaller one, what longest side of the smaller one, that's 9. Because of this point, decimal place, you multiply by 10. So, when you multiply, because of the decimal place, to take it off, you are going to be having 2.5,...”
- 28:50 “We said that solution. A scalar factor is that of the longest. The longest, the first side given, the first side given is the wall. The longest, remember, over longest of the beak, those sides that are given, and the lon...”
Roots of Quadratic Equations
This lesson covers how to find the sum and product of the roots of a quadratic equation. It also explains how to form a quadratic equation given the roots and states the conditions for equal roots, real roots, and no roots. Additionally, it discusses the relationship between a line and a curve in te
- 15:18 “you can just make it three X over two, and you now go for minus two of five times X, that gives you minus two X over five. And the last one minus two of five times three over two, that gives you minus, okay, six over 10....”
Factorization of Algebraic Expressions
This lesson covers the factorization of simple algebraic expressions and quadratic expressions. It includes methods for identifying factors and solving related word problems.
- 18:06 “So if these are in a perfect square, it's easy, very easy. So you put it in square and you express this how, how do you break it out? So someone says, oh, it becomes simpler. So I have a solution to the problem. Now, thi...”
- 05:25 “and x becomes their common factors. So, 5x plus 10x will have the common factor to be 5 multiplied by y. So, therefore, now, we pick up with another one, another question. Now, still repeating the same process, still rep...”
- 24:25 “be twice of that of girls. And what's girls? X. So, it would be two times X. That gives me word, two X. Someone said, oh, are you manipulating it out? I'm following street instruction. In what problem? Don't manipulate w...”
Rational and Non-Rational Numbers
This lesson covers the identification of rational and non-rational numbers. It explains the characteristics of different number sets, including natural numbers, whole numbers, and integers. The lesson also discusses the significance of the number PI in relation to circles.
- 18:13 “That's 10 times 10. 10 in two forms. That's 10 times 10. 10 in two form. 10 times 10. 10 times 10. Now, going forward, we have that gives categorically equal to 3.14.1.6 divided by 10 times 10 is 100. 100. So, we have 3....”
- 15:03 “So I put it. So simply, move it. I have my pie is what my circumference is given. The circumference is given in 62.832 over what's my radios? My radios is 10. That is 10. Now, I have 2 radios makes 1 diameter. That's tim...”
- 08:46 “In on-dread. So I will just simply have it as 3 over 100. Like this. So I have 72%, that's 72 by 100, 120%. And what are the percentage? So in all categories, they all fall on that award. The rational numbers. Now, movin...”
Translating Word Problems into Equations
The lesson teaches how to translate word sentences into mathematical equations. It covers the use of variables to represent numbers and how to express word problems as algebraic expressions. Students will learn to solve simple equations and check their answers.
- 03:09 “can easily be put simple. The entire word here can just be put simple, simply like this, with algebraic expressions. Use footsteps in solving world problems with our algebraic expressions. For example, you have three con...”
- 05:32 “Just as your age is maybe two years old. Or 3, 5, 12, like that. So we don't know the exact value we represented it with X years old. Our horde will be his daughter. Then his daughter is currently at the moment, half is...”
- 03:58 “That is X plus five. Because I haven't mentioned how much I earn. So how much I earn can be represented with X. So if how much my brother earns is X, or X in the era, and I say I earn five NARA more than my brother, that...”
Chemical Symbols and Formulae
The lesson covers the symbols of the first 20 elements and how to write chemical formulae and equations. It explains the differences between elements, compounds, and mixtures, as well as the concept of radicals and valency. The laws of conservation of mass and constant composition are also discussed
- 14:44 “that nitrogen with balance, nitrogen with balance A. My hydrogen is balanced, my nitrogen is balanced. The next I need to balance is oxygen. How many oxygen do I have now on the product side? I have 3 A, 2 A, making 5 ox...”
Counting in Binary
This lesson teaches how to count using the binary system, which uses only the digits zero and one. Students will learn to represent numbers in base two and understand the place values associated with binary digits. Activities include grouping counters to illustrate binary numbers.
- 04:52 “One, two, three, then four. Then I have one left. Okay, let's continue the activity. Then next one now is to group them in eight, four, two, and units. Okay, let's see, let's do that now. We've grouped this into, now let...”
Change of Subject of Formula
This lesson teaches how to change the subject of a formula using the substitution method. It explains the concept of the subject of a formula and provides examples of changing one variable to another. The process involves identifying the current subject and applying inverse operations.
- 11:09 “both sides by A. So when I take out divide both sides by A, what am I left with? So what I have, V minus U over A equal to A T divided by A, taking the addition. So this goes this. So what do I have left in my system of...”
Solving Simultaneous Linear Equations
This lesson covers how to solve simultaneous linear equations using substitution and elimination methods. It also explains how to identify linear equations and includes examples for practice.
- 17:47 “Divide by 2. If I divide by 2, I'm going to have 5 over 2P plus 2R divided by 2. That gives us R. Then 2 divided by 2, I have 1 here. Code is equation 3. Now I can combine 1 and 3 together now. 1P plus R equals 1 over 4....”
- 06:38 “4R and 6. Divide 3 by 4. Divide 3 by 4. R equals to 4 divided by 4 will give you 1. Then, you have your R. 2R is what? 2R is what? Now, I have my value of R to be 3 over 2. Don't forget we are using some decision method....”